Occasionally, people decide to use liquid fuels, like gasoline, in
place of the
more common gaseous fuels like propane, in a combustion spud gun. This
page contains
information
on some of the common liquid fuels that might be used in a spud gun.
In order for combustion to occur you need two things, fuel and
oxygen.
In a typical spudgun, air is the source of the oxygen and the fuel is a
gaseous hydrocarbon such as propane. Here, we will be looking at the
use
of liquid fuels such as gasoline. Regardless of whether you use a
gaseous or liquid fuel,
the ratio of fuel to oxygen must be correct to get the maximum amount
of power
out of your gun. Furthermore, to get the fuel to even ignite is must be
within the fuel's combustibility limits.
The complete combustion of hydrocarbon fuels using oxygen (O2) produces carbon dioxide (CO2), water and heat. As an example, the balanced (stoichiometric) chemical equation for the complete combustion of octane (C8H18, a major component of gasoline) in oxygen is;
2C8H18 + 25O2 = 16CO2 + 18H20 + Heat
This equation tells us that for each molecule of octane we need 25/2=12.5 molecules of oxygen. If we have either too much or too little fuel, the reaction does not go to completion and the energy released by the combustion is decreased.
Most fuels only burn over a limited range of concentrations
in air. For octane, that range is about 1% to 6.5%. If we
have less than 1% octane, or more than 6.5% octane, the octane will
not
burn. So, too much fuel, or too little fuel, will simply not
ignite. The
optimal amount of fuel is what is predicted by the combustion equation,
the volume of the chamber,
and the percentage of oxygen in air. Too
much fuel will never cause
a spudgun to fail since with too much fuel the gun won't fire.
For each fuel the maximum energy will be produced when the ratio of fuel to oxygen is correct for the particular fuel. However, most spudguns use air as the oxygen source instead of pure oxygen. Air is about 21% oxygen (by volume), 88% nitrogen and about 1% other gases. We have to take this into account when calculating the amount of fuel to use in a gun. The chemical equation for the combustion of octane indicates that we need 12.5 volumes of oxygen per (gaseous) volume of octane. Since air is 21% oxygen then we need about (1/12.5)(21%) = 1.7% by volume gaseous octane in the chamber with air for maximum power.
With liquid fuels we have a couple of problems not present with
gaseous
fuels, for example;
One thing that you should keep in mind with liquid
fuels
is the
potential for weakening the PVC. Take a look at the ingredients list on
your cans of PVC cleaner and glue. Anything listed on those cans
probably should
be avoided as fuels. Acetone and tetrahydrofuran (THF) in
particular are probably not the best idea for fuel since they are
present in PVC glue and cleaner and will soften
and/or be absorbed by the PVC. PVC should be fine with small amounts of
gasoline.
In order to calculate the volume of a liquid fuel for a particular sized gun we need several pieces of information; the volume of the chamber (from which the volume of available oxygen can be calculated), the molecular weight (MW, in grams/mol) of the fuel, the density (in g/ml) of the liquid fuel and the amount of oxygen required per mole of fuel. The volume of liquid fuel required is given by;
| (Vchamber)(0.01639L/in3)(273.15/Temp)*(1mol/22.4L)*(MW in g/mol)(mol fuel/mol oxygen)(0.2095) |
|
|
| (density of liquid fuel in g/ml) |
Where, Vchamber is the volume of the chamber
(in in3), and Temp
is the
ambient temperature in degrees kelvin (72F=295K). The ratio "mol fuel/mol oxygen" is the
number of molecules of fuel per molecule of oxygen from the balanced
chemical equation for the combustion. The factor of 0.2095 is the
mole fraction of oxygen in air. The 0.0164L/in3 factor
converts the chamber volume in in3 to liters.
As an example lets do octane (basically gasoline). The "mol fuel/mol oxygen" is 0.08 (2 molecules of octane for 25 molecules of oxygen), the density is 0.70g/ml, the MW is 114g/mol and we will assume a temperature of 72F (295K) and a chamber volume of 100in3 (1.64L). Plugging these values into the equation we get;
| (100in3)(0.0164L/in3)(273K/295K)*(1mol/22.4L)*(114g/mol oct.)(0.08 mol oct./mol O2)(0.2095) |
|
|
| (0.70g oct./ml oct.) |
| = 0.185ml octane |
So, for a
100in3 chamber filled with air we need to add
0.185ml of liquid octane. The parameters of several other liquid fuels
are given in Table I.
| Fuel | Boiling
Point, C (F) |
MW, g/mol | Density, g/ml | Heat
of
Combust., KJ/mol (note 1) |
Flammability Limits in Air | Stoich. % Fuel in Air | Energy Relative to Propane | Combustion Formula |
Moles fuel to moles oxygen | ml
per 100in3
Chamber Volume (note 2) |
Approx.
drops per 100in3 Chamber Volume (note 3) |
|---|---|---|---|---|---|---|---|---|---|---|---|
| Methanol (wood alcohol) |
65 (149) |
32 | 0.79 | 725 | 6%–36% | 14.0% | 1.09 | 2CH4O + 3O2 = 2CO2 + 4H2O |
0.667 | 0.384 | 4.7 |
| Ethanol (grain alcohol) |
78 (172) |
46 | 0.79 | 1378 | 3.3%–24.5% | 7.0% | 1.04 | 1C2H6O + 3O2 = 2CO2 + 3H2O |
0.333 | 0.277 | 3.4 |
| Isopropanol (rubbing alcohol) |
83 (181) |
60 | 0.79 | 2030 | 2%–12% | 4.7% | 1.02 | 2C3H8O + 9O2 = 6CO2 + 8H2O |
0.222 | 0.241 | 2.9 |
| Acetone | 57 (134) |
58 | 0.78 | 1761 | 2.6%–12.8% | 5.2% | 1.00 | 1C3H6O + 4O2 = 3CO2 + 3H2O |
0.250 | 0.262 | 3.2 |
| Diethyl Ether | 34.6 (94) |
74 | 0.71 | 2683 | 1.7%–48% | 3.5% | 1.01 | 1C4H10O + 6O2 = 4CO2 + 5H2O |
0.167 | 0.245 | 3.0 |
| Hexane | 69 (156) |
86 | 0.65 | 4167 | 1.2%–7.7% | 2.2% | 0.99 | 2C6H14 + 19O2 = 12CO2 + 14H2O |
0.105 | 0.196 | 2.4 |
| Octane (gasoline) |
126 (258) |
114 | 0.70 | 5473 | 1%–6.5% | 1.7% | 0.99 | 2C8H18 + 25O2 = 16CO2 + 18H2O |
0.080 | 0.184 | 2.2 |
| Toluene (methyl benzene) |
111 (231) |
92 | 0.86 | 4234 | 1.1%–7.1% | 2.3% | 1.07 | 1C7H8 + 9O2 = 7CO2 + 4H2O |
0.111 | 0.168 | 2.0 |
| Propane (for reference) |
-42 (-44) |
44 | 0.51 | 2208 | 2.37%–9.5% | 4.2% | 1 | 1C3H8 + 5O2 = 3CO2 + 4H2O |
0.200 |
Table Notes:
For our 100in3 chamber we determined we needed 0.185ml
(about 1/26th of a teaspoon) of
liquid octane (gasoline). How exactly do you measure a volume that
small?
Well, 1 drop of a liquid is generally about 0.08ml (this is very
approximate and depends on the shape of the dropper and the viscosity
of the liquid). So 0.185ml would
be about 2.3 drops.
If you try to draw a volatile (low boiling) liquid, like gasoline,
up
into an eye dropper the liquid will piddle back out of the dropper
almost immediately. This is caused by the evaporation of the volatile
liquid which raises the pressure in the dropper. To minimize
this affect you can draw the liquid up into the dropper, allow most of
the liquid to be pushed out of the dropper, then refill the dropper. If
you repeat this process several times eventually the liquid will, more
or
less, stay in the dropper for the length of time needed to measure it
into your chamber. By repeatedly filling and draining the dropper you
are replacing the air in the dropper with fuel vapor. Once
the dropper is full of fuel vapor the liquid will stop evaporating.
You may want to do a rough calibration of your eye dropper with your chosen fuel. Measure how many drops it takes to fill a 1/4 teaspoon measure (1/4 teaspoon = 1.225ml), it should be somewhere around 15 +/- 5 drops. Divide the actual number of drops you measured 15 by and use this number as a scaling factor for the values in the column "Approx. drops per 100in3 Chamber Volume" in Table I .
| (measured number drops in 1/4 teaspoon)( Approx. drops per 100in3 Chamber Volume) | ||
| corrected number drops | = |
|
| 15 |
Now that we know how many drops of fuel are required, and we can
measure the number of drops with reasonable accuracy, we need to make
sure that the fuel actually evaporates once it is inside the chamber.
For best results, this is going to require a chamber fan. I suggest
adding the appropriate number of drops of fuel to the chamber, closing
the chamber and running the fan for ten seconds or so. Open the chamber
up and see if the drops of fuel are still present. If they are then
you need to run the fan longer. Do this a couple of times until you
have a good idea of how long the particular fuel takes to evaporate
with your fan setup.
When you are ready to actually fire the gun you should thoroughly
air out the test fuel load(s) from the chamber, measure in new fuel,
close the chamber and run the fan. Do not open the chamber to check for
complete evaporation since you will loose some of your fuel.
The "heat of combustion" of a fuel is a measure of the amount of energy released when the fuel is burned. This is an important, but not the only factor affecting the performance of a fuel. The table above lists the heats of combustion along with other parameters for a variety of liquid fuels.
The key value for comparing two fuels is not the heats of combustion. Instead, you need to take into account both the heat of combustion and the amount of oxygen required to burn the fuel. The amount of fuel that should be used is limited by the amount of oxygen present in the chamber. Fuel is added to match that amount of oxygen. In the table, the "Energy Relative to Propane" column gives the theoretical amount of energy that can be obtained for a particular fuel, relative to the energy with propane as the fuel. A graph of the relative energies is shown below.

As you can see from the graph, there is relatively little energy difference between the various fuels. The best fuel in the set, by this measure, is methanol which gives 9% more energy than propane. The worst fuel is octane (gasoline) which gives about 1% less energy than propane.
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Modified: 25 June
2007
©2007 James Sluka